2(y-3)-2=-3(-5y+2)-5y

Solution for 2(y-3)-2=-3(-5y+2)-5y equation:

2(y-3)-2=-3(-5y+2)-5y

We move all terms to the left:

2(y-3)-2-(-3(-5y+2)-5y)=0

We multiply parentheses

2y-(-3(-5y+2)-5y)-6-2=0


We calculate terms in parentheses: -(-3(-5y+2)-5y), so:

-3(-5y+2)-5y

We add all the numbers together, and all the variables

-5y-3(-5y+2)

We multiply parentheses

-5y+15y-6

We add all the numbers together, and all the variables

10y-6

Back to the equation:

-(10y-6)


We add all the numbers together, and all the variables

2y-(10y-6)-8=0

We get rid of parentheses

2y-10y+6-8=0

We add all the numbers together, and all the variables

-8y-2=0

We move all terms containing y to the left, all other terms to the right

-8y=2

y=2/-8

y=-1/4