2(y-3)(-y-3)=0

Solution for 2(y-3)(-y-3)=0 equation:

2(y-3)(-y-3)=0

We add all the numbers together, and all the variables

2(y-3)(-1y-3)=0

We multiply parentheses ..

2(-1y^2-3y+3y+9)=0

We multiply parentheses

-2y^2-6y+6y+18=0

We add all the numbers together, and all the variables

-2y^2+18=0

a = -2; b = 0; c = +18;
Δ = b2-4ac
Δ = 02-4·(-2)·18
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12}{2*-2}=\frac{-12}{-4}
=+3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12}{2*-2}=\frac{12}{-4}
=-3
$