2(y-2)=4y+3-2(-2y-4)

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Solution for 2(y-2)=4y+3-2(-2y-4) equation: 



2(y-2)=4y+3-2(-2y-4)

We move all terms to the left:

2(y-2)-(4y+3-2(-2y-4))=0

We multiply parentheses

2y-(4y+3-2(-2y-4))-4=0



We calculate terms in parentheses: -(4y+3-2(-2y-4)), so:

4y+3-2(-2y-4)

determiningTheFunctionDomain
4y-2(-2y-4)+3

We multiply parentheses

4y+4y+8+3

We add all the numbers together, and all the variables

8y+11

Back to the equation:

-(8y+11)



We get rid of parentheses

2y-8y-11-4=0

We add all the numbers together, and all the variables

-6y-15=0

We move all terms containing y to the left, all other terms to the right

-6y=15

y=15/-6

y=-2+1/2

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