2(y-2)=4(y+4)-6

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Solution for 2(y-2)=4(y+4)-6 equation: 



2(y-2)=4(y+4)-6

We move all terms to the left:

2(y-2)-(4(y+4)-6)=0

We multiply parentheses

2y-(4(y+4)-6)-4=0



We calculate terms in parentheses: -(4(y+4)-6), so:

4(y+4)-6

We multiply parentheses

4y+16-6

We add all the numbers together, and all the variables

4y+10

Back to the equation:

-(4y+10)



We get rid of parentheses

2y-4y-10-4=0

We add all the numbers together, and all the variables

-2y-14=0

We move all terms containing y to the left, all other terms to the right

-2y=14

y=14/-2

y=-7

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