2(y-2)+18=-2(y-1)+6y

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Solution for 2(y-2)+18=-2(y-1)+6y equation: 



2(y-2)+18=-2(y-1)+6y

We move all terms to the left:

2(y-2)+18-(-2(y-1)+6y)=0

We multiply parentheses

2y-(-2(y-1)+6y)-4+18=0



We calculate terms in parentheses: -(-2(y-1)+6y), so:

-2(y-1)+6y

We add all the numbers together, and all the variables

6y-2(y-1)

We multiply parentheses

6y-2y+2

We add all the numbers together, and all the variables

4y+2

Back to the equation:

-(4y+2)



We add all the numbers together, and all the variables

2y-(4y+2)+14=0

We get rid of parentheses

2y-4y-2+14=0

We add all the numbers together, and all the variables

-2y+12=0

We move all terms containing y to the left, all other terms to the right

-2y=-12

y=-12/-2

y=+6

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