2(y-1)+3(y-2)=4(y-3)

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Solution for 2(y-1)+3(y-2)=4(y-3) equation: 



2(y-1)+3(y-2)=4(y-3)

We move all terms to the left:

2(y-1)+3(y-2)-(4(y-3))=0

We multiply parentheses

2y+3y-(4(y-3))-2-6=0



We calculate terms in parentheses: -(4(y-3)), so:

4(y-3)

We multiply parentheses

4y-12

Back to the equation:

-(4y-12)



We add all the numbers together, and all the variables

5y-(4y-12)-8=0

We get rid of parentheses

5y-4y+12-8=0

We add all the numbers together, and all the variables

y+4=0

We move all terms containing y to the left, all other terms to the right

y=-4

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