2(y+6)=3(y-2)

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Solution for 2(y+6)=3(y-2) equation:



2(y+6)=3(y-2)
We move all terms to the left:
2(y+6)-(3(y-2))=0
We multiply parentheses
2y-(3(y-2))+12=0
We calculate terms in parentheses: -(3(y-2)), so:
3(y-2)
We multiply parentheses
3y-6
Back to the equation:
-(3y-6)
We get rid of parentheses
2y-3y+6+12=0
We add all the numbers together, and all the variables
-1y+18=0
We move all terms containing y to the left, all other terms to the right
-y=-18
y=-18/-1
y=+18

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