2(y+5)=-2(6y-2)+2y

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Solution for 2(y+5)=-2(6y-2)+2y equation: 



2(y+5)=-2(6y-2)+2y

We move all terms to the left:

2(y+5)-(-2(6y-2)+2y)=0

We multiply parentheses

2y-(-2(6y-2)+2y)+10=0



We calculate terms in parentheses: -(-2(6y-2)+2y), so:

-2(6y-2)+2y

We add all the numbers together, and all the variables

2y-2(6y-2)

We multiply parentheses

2y-12y+4

We add all the numbers together, and all the variables

-10y+4

Back to the equation:

-(-10y+4)



We get rid of parentheses

2y+10y-4+10=0

We add all the numbers together, and all the variables

12y+6=0

We move all terms containing y to the left, all other terms to the right

12y=-6

y=-6/12

y=-1/2

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