2(y+4)=6(2-y)

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Solution for 2(y+4)=6(2-y) equation:



2(y+4)=6(2-y)
We move all terms to the left:
2(y+4)-(6(2-y))=0
We add all the numbers together, and all the variables
2(y+4)-(6(-1y+2))=0
We multiply parentheses
2y-(6(-1y+2))+8=0
We calculate terms in parentheses: -(6(-1y+2)), so:
6(-1y+2)
We multiply parentheses
-6y+12
Back to the equation:
-(-6y+12)
We get rid of parentheses
2y+6y-12+8=0
We add all the numbers together, and all the variables
8y-4=0
We move all terms containing y to the left, all other terms to the right
8y=4
y=4/8
y=1/2

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