2(y+4)+2(y+4)=22

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Solution for 2(y+4)+2(y+4)=22 equation: 



2(y+4)+2(y+4)=22

We move all terms to the left:

2(y+4)+2(y+4)-(22)=0

We multiply parentheses

2y+2y+8+8-22=0

We add all the numbers together, and all the variables

4y-6=0

We move all terms containing y to the left, all other terms to the right

4y=6

y=6/4

y=1+1/2

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