2(y+4)+2(3y-1)=30

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Solution for 2(y+4)+2(3y-1)=30 equation: 



2(y+4)+2(3y-1)=30

We move all terms to the left:

2(y+4)+2(3y-1)-(30)=0

We multiply parentheses

2y+6y+8-2-30=0

We add all the numbers together, and all the variables

8y-24=0

We move all terms containing y to the left, all other terms to the right

8y=24

y=24/8

y=3

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