2(y+3)=48

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Solution for 2(y+3)=48 equation: 



2(y+3)=48

We move all terms to the left:

2(y+3)-(48)=0

We multiply parentheses

2y+6-48=0

We add all the numbers together, and all the variables

2y-42=0

We move all terms containing y to the left, all other terms to the right

2y=42

y=42/2

y=21

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