2(y+3)=3(3y-1)

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Solution for 2(y+3)=3(3y-1) equation: 



2(y+3)=3(3y-1)

We move all terms to the left:

2(y+3)-(3(3y-1))=0

We multiply parentheses

2y-(3(3y-1))+6=0



We calculate terms in parentheses: -(3(3y-1)), so:

3(3y-1)

We multiply parentheses

9y-3

Back to the equation:

-(9y-3)



We get rid of parentheses

2y-9y+3+6=0

We add all the numbers together, and all the variables

-7y+9=0

We move all terms containing y to the left, all other terms to the right

-7y=-9

y=-9/-7

y=1+2/7

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