2(y+3)-5(y-1)=32

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Solution for 2(y+3)-5(y-1)=32 equation: 



2(y+3)-5(y-1)=32

We move all terms to the left:

2(y+3)-5(y-1)-(32)=0

We multiply parentheses

2y-5y+6+5-32=0

We add all the numbers together, and all the variables

-3y-21=0

We move all terms containing y to the left, all other terms to the right

-3y=21

y=21/-3

y=-7

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