2(y+3)-2=7y-1

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Solution for 2(y+3)-2=7y-1 equation: 



2(y+3)-2=7y-1

We move all terms to the left:

2(y+3)-2-(7y-1)=0

We multiply parentheses

2y-(7y-1)+6-2=0

We get rid of parentheses

2y-7y+1+6-2=0

We add all the numbers together, and all the variables

-5y+5=0

We move all terms containing y to the left, all other terms to the right

-5y=-5

y=-5/-5

y=1

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