2(y+3)+3(2y-1)=11

Solution for 2(y+3)+3(2y-1)=11 equation:

Simplifying
2(y + 3) + 3(2y + -1) = 11

Reorder the terms:
2(3 + y) + 3(2y + -1) = 11
(3 * 2 + y * 2) + 3(2y + -1) = 11
(6 + 2y) + 3(2y + -1) = 11

Reorder the terms:
6 + 2y + 3(-1 + 2y) = 11
6 + 2y + (-1 * 3 + 2y * 3) = 11
6 + 2y + (-3 + 6y) = 11

Reorder the terms:
6 + -3 + 2y + 6y = 11

Combine like terms: 6 + -3 = 3
3 + 2y + 6y = 11

Combine like terms: 2y + 6y = 8y
3 + 8y = 11

Solving
3 + 8y = 11

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 8y = 11 + -3

Combine like terms: 3 + -3 = 0
0 + 8y = 11 + -3
8y = 11 + -3

Combine like terms: 11 + -3 = 8
8y = 8

Divide each side by '8'.
y = 1

Simplifying
y = 1