2(y+2)=3(y-4)

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Solution for 2(y+2)=3(y-4) equation:


Simplifying
2(y + 2) = 3(y + -4)

Reorder the terms:
2(2 + y) = 3(y + -4)
(2 * 2 + y * 2) = 3(y + -4)
(4 + 2y) = 3(y + -4)

Reorder the terms:
4 + 2y = 3(-4 + y)
4 + 2y = (-4 * 3 + y * 3)
4 + 2y = (-12 + 3y)

Solving
4 + 2y = -12 + 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.
4 + 2y + -3y = -12 + 3y + -3y

Combine like terms: 2y + -3y = -1y
4 + -1y = -12 + 3y + -3y

Combine like terms: 3y + -3y = 0
4 + -1y = -12 + 0
4 + -1y = -12

Add '-4' to each side of the equation.
4 + -4 + -1y = -12 + -4

Combine like terms: 4 + -4 = 0
0 + -1y = -12 + -4
-1y = -12 + -4

Combine like terms: -12 + -4 = -16
-1y = -16

Divide each side by '-1'.
y = 16

Simplifying
y = 16

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