2(y+2)+2=29-2(y+3)

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Solution for 2(y+2)+2=29-2(y+3) equation: 



2(y+2)+2=29-2(y+3)

We move all terms to the left:

2(y+2)+2-(29-2(y+3))=0

We multiply parentheses

2y-(29-2(y+3))+4+2=0



We calculate terms in parentheses: -(29-2(y+3)), so:

29-2(y+3)

determiningTheFunctionDomain
-2(y+3)+29

We multiply parentheses

-2y-6+29

We add all the numbers together, and all the variables

-2y+23

Back to the equation:

-(-2y+23)



We add all the numbers together, and all the variables

2y-(-2y+23)+6=0

We get rid of parentheses

2y+2y-23+6=0

We add all the numbers together, and all the variables

4y-17=0

We move all terms containing y to the left, all other terms to the right

4y=17

y=17/4

y=4+1/4

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