2(y+12)-6(y-3)=14

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Solution for 2(y+12)-6(y-3)=14 equation: 



2(y+12)-6(y-3)=14

We move all terms to the left:

2(y+12)-6(y-3)-(14)=0

We multiply parentheses

2y-6y+24+18-14=0

We add all the numbers together, and all the variables

-4y+28=0

We move all terms containing y to the left, all other terms to the right

-4y=-28

y=-28/-4

y=+7

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