2(y+1)=3(y-5)

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Solution for 2(y+1)=3(y-5) equation: 



2(y+1)=3(y-5)

We move all terms to the left:

2(y+1)-(3(y-5))=0

We multiply parentheses

2y-(3(y-5))+2=0



We calculate terms in parentheses: -(3(y-5)), so:

3(y-5)

We multiply parentheses

3y-15

Back to the equation:

-(3y-15)



We get rid of parentheses

2y-3y+15+2=0

We add all the numbers together, and all the variables

-1y+17=0

We move all terms containing y to the left, all other terms to the right

-y=-17

y=-17/-1

y=+17

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