2(y+1)=-2(6y-4)+6y

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Solution for 2(y+1)=-2(6y-4)+6y equation: 



2(y+1)=-2(6y-4)+6y

We move all terms to the left:

2(y+1)-(-2(6y-4)+6y)=0

We multiply parentheses

2y-(-2(6y-4)+6y)+2=0



We calculate terms in parentheses: -(-2(6y-4)+6y), so:

-2(6y-4)+6y

We add all the numbers together, and all the variables

6y-2(6y-4)

We multiply parentheses

6y-12y+8

We add all the numbers together, and all the variables

-6y+8

Back to the equation:

-(-6y+8)



We get rid of parentheses

2y+6y-8+2=0

We add all the numbers together, and all the variables

8y-6=0

We move all terms containing y to the left, all other terms to the right

8y=6

y=6/8

y=3/4

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