2(y+1)=-2(5y-2)+4y

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Solution for 2(y+1)=-2(5y-2)+4y equation: 



2(y+1)=-2(5y-2)+4y

We move all terms to the left:

2(y+1)-(-2(5y-2)+4y)=0

We multiply parentheses

2y-(-2(5y-2)+4y)+2=0



We calculate terms in parentheses: -(-2(5y-2)+4y), so:

-2(5y-2)+4y

We add all the numbers together, and all the variables

4y-2(5y-2)

We multiply parentheses

4y-10y+4

We add all the numbers together, and all the variables

-6y+4

Back to the equation:

-(-6y+4)



We get rid of parentheses

2y+6y-4+2=0

We add all the numbers together, and all the variables

8y-2=0

We move all terms containing y to the left, all other terms to the right

8y=2

y=2/8

y=1/4

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