2(y+1)-4(y-3)=6y+14-8y

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Solution for 2(y+1)-4(y-3)=6y+14-8y equation:


Simplifying
2(y + 1) + -4(y + -3) = 6y + 14 + -8y

Reorder the terms:
2(1 + y) + -4(y + -3) = 6y + 14 + -8y
(1 * 2 + y * 2) + -4(y + -3) = 6y + 14 + -8y
(2 + 2y) + -4(y + -3) = 6y + 14 + -8y

Reorder the terms:
2 + 2y + -4(-3 + y) = 6y + 14 + -8y
2 + 2y + (-3 * -4 + y * -4) = 6y + 14 + -8y
2 + 2y + (12 + -4y) = 6y + 14 + -8y

Reorder the terms:
2 + 12 + 2y + -4y = 6y + 14 + -8y

Combine like terms: 2 + 12 = 14
14 + 2y + -4y = 6y + 14 + -8y

Combine like terms: 2y + -4y = -2y
14 + -2y = 6y + 14 + -8y

Reorder the terms:
14 + -2y = 14 + 6y + -8y

Combine like terms: 6y + -8y = -2y
14 + -2y = 14 + -2y

Add '-14' to each side of the equation.
14 + -14 + -2y = 14 + -14 + -2y

Combine like terms: 14 + -14 = 0
0 + -2y = 14 + -14 + -2y
-2y = 14 + -14 + -2y

Combine like terms: 14 + -14 = 0
-2y = 0 + -2y
-2y = -2y

Add '2y' to each side of the equation.
-2y + 2y = -2y + 2y

Combine like terms: -2y + 2y = 0
0 = -2y + 2y

Combine like terms: -2y + 2y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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