2(y+1)+4y=3(2y-1)=8

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Solution for 2(y+1)+4y=3(2y-1)=8 equation: 



2(y+1)+4y=3(2y-1)=8

We move all terms to the left:

2(y+1)+4y-(3(2y-1))=0

We add all the numbers together, and all the variables

4y+2(y+1)-(3(2y-1))=0

We multiply parentheses

4y+2y-(3(2y-1))+2=0



We calculate terms in parentheses: -(3(2y-1)), so:

3(2y-1)

We multiply parentheses

6y-3

Back to the equation:

-(6y-3)



We add all the numbers together, and all the variables

6y-(6y-3)+2=0

We get rid of parentheses

6y-6y+3+2=0

We add all the numbers together, and all the variables

5!=0

There is no solution for this equation

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