2(y+1)+4=3(2y-1)+8

Solution for 2(y+1)+4=3(2y-1)+8 equation:

Simplifying
2(y + 1) + 4 = 3(2y + -1) + 8

Reorder the terms:
2(1 + y) + 4 = 3(2y + -1) + 8
(1 * 2 + y * 2) + 4 = 3(2y + -1) + 8
(2 + 2y) + 4 = 3(2y + -1) + 8

Reorder the terms:
2 + 4 + 2y = 3(2y + -1) + 8

Combine like terms: 2 + 4 = 6
6 + 2y = 3(2y + -1) + 8

Reorder the terms:
6 + 2y = 3(-1 + 2y) + 8
6 + 2y = (-1 * 3 + 2y * 3) + 8
6 + 2y = (-3 + 6y) + 8

Reorder the terms:
6 + 2y = -3 + 8 + 6y

Combine like terms: -3 + 8 = 5
6 + 2y = 5 + 6y

Solving
6 + 2y = 5 + 6y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6y' to each side of the equation.
6 + 2y + -6y = 5 + 6y + -6y

Combine like terms: 2y + -6y = -4y
6 + -4y = 5 + 6y + -6y

Combine like terms: 6y + -6y = 0
6 + -4y = 5 + 0
6 + -4y = 5

Add '-6' to each side of the equation.
6 + -6 + -4y = 5 + -6

Combine like terms: 6 + -6 = 0
0 + -4y = 5 + -6
-4y = 5 + -6

Combine like terms: 5 + -6 = -1
-4y = -1

Divide each side by '-4'.
y = 0.25

Simplifying
y = 0.25