2(y+1)+4=2(y-1)+y

Solution for 2(y+1)+4=2(y-1)+y equation:

2(y+1)+4=2(y-1)+y

We move all terms to the left:

2(y+1)+4-(2(y-1)+y)=0

We multiply parentheses

2y-(2(y-1)+y)+2+4=0


We calculate terms in parentheses: -(2(y-1)+y), so:

2(y-1)+y

We add all the numbers together, and all the variables

y+2(y-1)

We multiply parentheses

y+2y-2

We add all the numbers together, and all the variables

3y-2

Back to the equation:

-(3y-2)


We add all the numbers together, and all the variables

2y-(3y-2)+6=0

We get rid of parentheses

2y-3y+2+6=0

We add all the numbers together, and all the variables

-1y+8=0

We move all terms containing y to the left, all other terms to the right

-y=-8

y=-8/-1

y=+8