2(y+1)+3(y-2)=12

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Solution for 2(y+1)+3(y-2)=12 equation: 


Simplifying
2(y + 1) + 3(y + -2) = 12

Reorder the terms:
2(1 + y) + 3(y + -2) = 12
(1 * 2 + y * 2) + 3(y + -2) = 12
(2 + 2y) + 3(y + -2) = 12

Reorder the terms:
2 + 2y + 3(-2 + y) = 12
2 + 2y + (-2 * 3 + y * 3) = 12
2 + 2y + (-6 + 3y) = 12

Reorder the terms:
2 + -6 + 2y + 3y = 12

Combine like terms: 2 + -6 = -4
-4 + 2y + 3y = 12

Combine like terms: 2y + 3y = 5y
-4 + 5y = 12

Solving
-4 + 5y = 12

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 5y = 12 + 4

Combine like terms: -4 + 4 = 0
0 + 5y = 12 + 4
5y = 12 + 4

Combine like terms: 12 + 4 = 16
5y = 16

Divide each side by '5'.
y = 3.2

Simplifying
y = 3.2

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