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2(x2-4x)=3x^2-(x2+4)
We move all terms to the left:
2(x2-4x)-(3x^2-(x2+4))=0
We add all the numbers together, and all the variables
2(+x^2-4x)-(3x^2-(+x^2+4))=0
We multiply parentheses
2x^2-(3x^2-(+x^2+4))-8x=0
We calculate terms in parentheses: -(3x^2-(+x^2+4)), so:We add all the numbers together, and all the variables
3x^2-(+x^2+4)
We get rid of parentheses
3x^2-x^2-4
We add all the numbers together, and all the variables
2x^2-4
Back to the equation:
-(2x^2-4)
2x^2-8x-(2x^2-4)=0
We get rid of parentheses
2x^2-2x^2-8x+4=0
We add all the numbers together, and all the variables
-8x+4=0
We move all terms containing x to the left, all other terms to the right
-8x=-4
x=-4/-8
x=1/2
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