2(x2-3)=x2-12

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Solution for 2(x2-3)=x2-12 equation: 



2(x2-3)=x2-12

We move all terms to the left:

2(x2-3)-(x2-12)=0

We add all the numbers together, and all the variables

2(+x^2-3)-(+x^2-12)=0

We multiply parentheses

2x^2-(+x^2-12)-6=0

We get rid of parentheses

2x^2-x^2+12-6=0

We add all the numbers together, and all the variables

x^2+6=0

a = 1; b = 0; c = +6;
Δ = b2-4ac
Δ = 02-4·1·6
Δ = -24
Delta is less than zero, so there is no solution for the equation

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