2(x2-1)=10-x2

Solution for 2(x2-1)=10-x2 equation:

2(x2-1)=10-x2

We move all terms to the left:

2(x2-1)-(10-x2)=0

We add all the numbers together, and all the variables

2(+x^2-1)-(-1x^2+10)=0

We multiply parentheses

2x^2-(-1x^2+10)-2=0

We get rid of parentheses

2x^2+1x^2-10-2=0

We add all the numbers together, and all the variables

3x^2-12=0

a = 3; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·3·(-12)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12}{2*3}=\frac{-12}{6}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12}{2*3}=\frac{12}{6}
=2
$