2(x2+4)=5

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Solution for 2(x2+4)=5 equation: 



2(x2+4)=5

We move all terms to the left:

2(x2+4)-(5)=0

We add all the numbers together, and all the variables

2(+x^2+4)-5=0

We multiply parentheses

2x^2+8-5=0

We add all the numbers together, and all the variables

2x^2+3=0

a = 2; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·2·3
Δ = -24
Delta is less than zero, so there is no solution for the equation

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