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2(x2)+8=121.5
We move all terms to the left:
2(x2)+8-(121.5)=0
We add all the numbers together, and all the variables
2x^2-113.5=0
a = 2; b = 0; c = -113.5;
Δ = b2-4ac
Δ = 02-4·2·(-113.5)
Δ = 908
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{908}=\sqrt{4*227}=\sqrt{4}*\sqrt{227}=2\sqrt{227}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{227}}{2*2}=\frac{0-2\sqrt{227}}{4} =-\frac{2\sqrt{227}}{4} =-\frac{\sqrt{227}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{227}}{2*2}=\frac{0+2\sqrt{227}}{4} =\frac{2\sqrt{227}}{4} =\frac{\sqrt{227}}{2} $
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