2(x/8+3)=7+1/4x

Solution for 2(x/8+3)=7+1/4x equation:

2(x/8+3)=7+1/4x

We move all terms to the left:

2(x/8+3)-(7+1/4x)=0


Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2(x/8+3)-(1/4x+7)=0

We multiply parentheses

2x-(1/4x+7)+6=0

We get rid of parentheses

2x-1/4x-7+6=0

We multiply all the terms by the denominator


2x*4x-7*4x+6*4x-1=0

Wy multiply elements

8x^2-28x+24x-1=0

We add all the numbers together, and all the variables

8x^2-4x-1=0

a = 8; b = -4; c = -1;
Δ = b2-4ac
Δ = -42-4·8·(-1)
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{3}}{2*8}=\frac{4-4\sqrt{3}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{3}}{2*8}=\frac{4+4\sqrt{3}}{16}
$