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2(x-8)=2x-2(x-3)
We move all terms to the left:
2(x-8)-(2x-2(x-3))=0
We multiply parentheses
2x-(2x-2(x-3))-16=0
We calculate terms in parentheses: -(2x-2(x-3)), so:We add all the numbers together, and all the variables
2x-2(x-3)
We multiply parentheses
2x-2x+6
We add all the numbers together, and all the variables
6
Back to the equation:
-(6)
2x-22=0
We move all terms containing x to the left, all other terms to the right
2x=22
x=22/2
x=11
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