2(x-7)+2x=4(x+2)-22

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Solution for 2(x-7)+2x=4(x+2)-22 equation: 



2(x-7)+2x=4(x+2)-22

We move all terms to the left:

2(x-7)+2x-(4(x+2)-22)=0

We add all the numbers together, and all the variables

2x+2(x-7)-(4(x+2)-22)=0

We multiply parentheses

2x+2x-(4(x+2)-22)-14=0



We calculate terms in parentheses: -(4(x+2)-22), so:

4(x+2)-22

We multiply parentheses

4x+8-22

We add all the numbers together, and all the variables

4x-14

Back to the equation:

-(4x-14)



We add all the numbers together, and all the variables

4x-(4x-14)-14=0

We get rid of parentheses

4x-4x+14-14=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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