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2(x-7)(3x+5)=0
We multiply parentheses ..
2(+3x^2+5x-21x-35)=0
We multiply parentheses
6x^2+10x-42x-70=0
We add all the numbers together, and all the variables
6x^2-32x-70=0
a = 6; b = -32; c = -70;
Δ = b2-4ac
Δ = -322-4·6·(-70)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2704}=52$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-52}{2*6}=\frac{-20}{12} =-1+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+52}{2*6}=\frac{84}{12} =7 $
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