2(x-6)-4(x+12)=2-4(x-12)

Solution for 2(x-6)-4(x+12)=2-4(x-12) equation:

2(x-6)-4(x+12)=2-4(x-12)

We move all terms to the left:

2(x-6)-4(x+12)-(2-4(x-12))=0

We multiply parentheses

2x-4x-(2-4(x-12))-12-48=0


We calculate terms in parentheses: -(2-4(x-12)), so:

2-4(x-12)

determiningTheFunctionDomain
-4(x-12)+2

We multiply parentheses

-4x+48+2

We add all the numbers together, and all the variables

-4x+50

Back to the equation:

-(-4x+50)


We add all the numbers together, and all the variables

-2x-(-4x+50)-60=0

We get rid of parentheses

-2x+4x-50-60=0

We add all the numbers together, and all the variables

2x-110=0

We move all terms containing x to the left, all other terms to the right

2x=110

x=110/2

x=55