2(x-6)-10=21x-212

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Solution for 2(x-6)-10=21x-212 equation: 



2(x-6)-10=21x-212

We move all terms to the left:

2(x-6)-10-(21x-212)=0

We multiply parentheses

2x-(21x-212)-12-10=0

We get rid of parentheses

2x-21x+212-12-10=0

We add all the numbers together, and all the variables

-19x+190=0

We move all terms containing x to the left, all other terms to the right

-19x=-190

x=-190/-19

x=+10

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