2(x-6)+4=8(1/2x-4

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Solution for 2(x-6)+4=8(1/2x-4 equation: 



2(x-6)+4=8(1/2x-4

We move all terms to the left:

2(x-6)+4-(8(1/2x-4)=0



Domain of the equation: 2x-4)+4!=0

x∈R



We multiply parentheses

2x-(8(1/2x-4)+4-12=0

We multiply all the terms by the denominator


2x*2x-4)+4-12-(8(1=0

We add all the numbers together, and all the variables

2x*2x=0

Wy multiply elements

4x^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{8}=0$

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