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2(x-6)+2x=4(x-3)
We move all terms to the left:
2(x-6)+2x-(4(x-3))=0
We add all the numbers together, and all the variables
2x+2(x-6)-(4(x-3))=0
We multiply parentheses
2x+2x-(4(x-3))-12=0
We calculate terms in parentheses: -(4(x-3)), so:We add all the numbers together, and all the variables
4(x-3)
We multiply parentheses
4x-12
Back to the equation:
-(4x-12)
4x-(4x-12)-12=0
We get rid of parentheses
4x-4x+12-12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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