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2(x-5)=3x-(x+10)
We move all terms to the left:
2(x-5)-(3x-(x+10))=0
We multiply parentheses
2x-(3x-(x+10))-10=0
We calculate terms in parentheses: -(3x-(x+10)), so:We get rid of parentheses
3x-(x+10)
We get rid of parentheses
3x-x-10
We add all the numbers together, and all the variables
2x-10
Back to the equation:
-(2x-10)
2x-2x+10-10=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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