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2(x-5)=3(x-2)+7
We move all terms to the left:
2(x-5)-(3(x-2)+7)=0
We multiply parentheses
2x-(3(x-2)+7)-10=0
We calculate terms in parentheses: -(3(x-2)+7), so:We get rid of parentheses
3(x-2)+7
We multiply parentheses
3x-6+7
We add all the numbers together, and all the variables
3x+1
Back to the equation:
-(3x+1)
2x-3x-1-10=0
We add all the numbers together, and all the variables
-1x-11=0
We move all terms containing x to the left, all other terms to the right
-x=11
x=11/-1
x=-11
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