2(x-5)=3(x+2)+7

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Solution for 2(x-5)=3(x+2)+7 equation: 



2(x-5)=3(x+2)+7

We move all terms to the left:

2(x-5)-(3(x+2)+7)=0

We multiply parentheses

2x-(3(x+2)+7)-10=0



We calculate terms in parentheses: -(3(x+2)+7), so:

3(x+2)+7

We multiply parentheses

3x+6+7

We add all the numbers together, and all the variables

3x+13

Back to the equation:

-(3x+13)



We get rid of parentheses

2x-3x-13-10=0

We add all the numbers together, and all the variables

-1x-23=0

We move all terms containing x to the left, all other terms to the right

-x=23

x=23/-1

x=-23

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