2(x-5)=3(2x+20)

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Solution for 2(x-5)=3(2x+20) equation: 



2(x-5)=3(2x+20)

We move all terms to the left:

2(x-5)-(3(2x+20))=0

We multiply parentheses

2x-(3(2x+20))-10=0



We calculate terms in parentheses: -(3(2x+20)), so:

3(2x+20)

We multiply parentheses

6x+60

Back to the equation:

-(6x+60)



We get rid of parentheses

2x-6x-60-10=0

We add all the numbers together, and all the variables

-4x-70=0

We move all terms containing x to the left, all other terms to the right

-4x=70

x=70/-4

x=-17+1/2

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