2(x-5)=3(-x+2)

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Solution for 2(x-5)=3(-x+2) equation: 



2(x-5)=3(-x+2)

We move all terms to the left:

2(x-5)-(3(-x+2))=0

We add all the numbers together, and all the variables

2(x-5)-(3(-1x+2))=0

We multiply parentheses

2x-(3(-1x+2))-10=0



We calculate terms in parentheses: -(3(-1x+2)), so:

3(-1x+2)

We multiply parentheses

-3x+6

Back to the equation:

-(-3x+6)



We get rid of parentheses

2x+3x-6-10=0

We add all the numbers together, and all the variables

5x-16=0

We move all terms containing x to the left, all other terms to the right

5x=16

x=16/5

x=3+1/5

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