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2(x-5)=12x+6(5-3x)
We move all terms to the left:
2(x-5)-(12x+6(5-3x))=0
We add all the numbers together, and all the variables
2(x-5)-(12x+6(-3x+5))=0
We multiply parentheses
2x-(12x+6(-3x+5))-10=0
We calculate terms in parentheses: -(12x+6(-3x+5)), so:We get rid of parentheses
12x+6(-3x+5)
We multiply parentheses
12x-18x+30
We add all the numbers together, and all the variables
-6x+30
Back to the equation:
-(-6x+30)
2x+6x-30-10=0
We add all the numbers together, and all the variables
8x-40=0
We move all terms containing x to the left, all other terms to the right
8x=40
x=40/8
x=5
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