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2(x-5)-8(x-6)=10
We move all terms to the left:
2(x-5)-8(x-6)-(10)=0
We multiply parentheses
2x-8x-10+48-10=0
We add all the numbers together, and all the variables
-6x+28=0
We move all terms containing x to the left, all other terms to the right
-6x=-28
x=-28/-6
x=4+2/3
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