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2(x-5)-3=29-5x
We move all terms to the left:
2(x-5)-3-(29-5x)=0
We add all the numbers together, and all the variables
2(x-5)-(-5x+29)-3=0
We multiply parentheses
2x-(-5x+29)-10-3=0
We get rid of parentheses
2x+5x-29-10-3=0
We add all the numbers together, and all the variables
7x-42=0
We move all terms containing x to the left, all other terms to the right
7x=42
x=42/7
x=6
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