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2(x-5)-2=x-12+x
We move all terms to the left:
2(x-5)-2-(x-12+x)=0
We add all the numbers together, and all the variables
2(x-5)-(2x-12)-2=0
We multiply parentheses
2x-(2x-12)-10-2=0
We get rid of parentheses
2x-2x+12-10-2=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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