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2(x-5)+5=4x-2(1+x)
We move all terms to the left:
2(x-5)+5-(4x-2(1+x))=0
We add all the numbers together, and all the variables
2(x-5)-(4x-2(x+1))+5=0
We multiply parentheses
2x-(4x-2(x+1))-10+5=0
We calculate terms in parentheses: -(4x-2(x+1)), so:We add all the numbers together, and all the variables
4x-2(x+1)
We multiply parentheses
4x-2x-2
We add all the numbers together, and all the variables
2x-2
Back to the equation:
-(2x-2)
2x-(2x-2)-5=0
We get rid of parentheses
2x-2x+2-5=0
We add all the numbers together, and all the variables
-3!=0
There is no solution for this equation
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